c++

At the moment I'm coding a small project for my university. I have to create a simple system on C# and Microsoft SQL Server 2005. So, I need a way (and code) to execute MS SQL Server's Stored Procedures from my C# program.

We have some additional letters in the Lithuanian language: ą, č, ę, ė, į, š, ų, ū, ž (if you can't see them - change the encoding of your browser into Unicode). The point is, that cout can not print those letters.

I have the fallowing situation. I have an object. I need to make a Dictionary, which contains all the properties (and it's values) of the object. Then send this Dictionary over the network.

private static void TestIntArray() { int [] array = new int[1000]; for (int i = 0; i < 1000; i++) array[i] = i; } private static void TestArrayList() { ArrayList array = new ArrayList(); for (int i = 0; i < 1000; i++) array.Add(i); } // Code.... long start = DateTime.Now.Ticks; TestIntArray(); long end = DateTime.Now.Ticks; Console.WriteLine("Time with int array: {0}", end - start); long start2 = DateTime.Now.Ticks; TestArrayList(); long end2 = DateTime.Now.Ticks; Console.WriteLine("Time with ArrayList array: {0}", end2 - start2);

The

I was browsing the web for information about the binary multiplication (also known as "left-to-right multiplication") in Ellipti curves. I wrote a demonstration of the algorithm. Unfortunately, it's very brief version, but it might be interesting for someone :) This demonstration generates the right point multiplication sequency in binary multiplication of point. First - very short theory. Point multiplication is the operation: Q = k∙P. Point multiplication is the combination of point doubling and point addition.

Simple example with interfaces.

In C we can use a function printf(), which can take different numbers of parameters. E.g.: printf("%d %s", a, b). How this can be done in C#? It can be done by keyword params: int Method(params int[] var) { int sum = 0; foreach (int i in var) sum += i; return sum; } // Code... Method(5, 2, 3); Method(64, 1); Method(9); More information: http://msdn.microsoft.com/en-us/library/w5zay9db(VS.71).aspx

I was browsing (ok, lets be honest - Goooogling) the web in order to find some Multiple-Precision Modular Arithmetics algorithms. Our lecturer recomended a very good book - "Handbook of Applied Cryptography".

Last weekend I had a problem.

Bandžiausi .NETo galimybes - kaip su gijomis draugaujama.

KTU'ne per .NET modulį davė parašyti dvi programėles. Viena iškviečia kitos Remote Object'ą. Kitaip tariant: veikia programa-serveris. Jinai turi žiauriai gerą ir naudingą metodą, kuriuo baisiai nori pasinaudoti programa-klientas.

Turbūt teko matyti įvairias konsolines programas, kuriose vienoje eilutėje rašomas besikeičiantis tekstas. Pavyzdžiui: turime instaliacijos sistemą. Instaliuojama programa. Rašomas progresas - bėga skaičiai nuo 1 iki 100 proc. Tačiau jei besikeičia vienoje eilutėje.

private static void insertEntryIntoArray(int insertationIndex, int entry, int [] array) { for (int i = array.length - 1; i > insertationIndex; i--) array[i] = array[i - 1]; array[insertationIndex] = entry; } // Kodas.... int [] array = new int[5]; int numberToInsert = 7; int entriesFilled = 3; array[0] = 1; array[1] = 5; array[2] = 10; for (int i = 0; i < entriesFilled; i++) if (array[i] > numberToInsert) { insertEntryIntoArray(i, numberToInsert, array); entriesFilled++; break; } Gal kam pravers :)

DataTable dataTable = new DataTable(); // Užpildome duomenimis string data = dataTable.Rows[indeksas] [stulpelio_pavadinimas].ToString(); Kažkas tokio: for (int i = 0; i < dataTable.Rows.Count; i++) Console.WriteLine(dataTable.Rows[i]["Vardas"].ToString();

Nusiskaitėme visą kelią iki failo, o mums reikia tik failo vardo. Kaip tai padaryti? Galima maždaug taip: OpenFileDialog openFileDialog = new OpenFileDialog(); if (openFileDialog.ShowDialog() == System.Windows.Forms.DialogResult.OK) { FileInfo fi = new FileInfo(openFileDialog.FileName); fi.Name; // Failo vardas fi.DirectoryName; // Kelias iki failo fi.Extension ; // Plėtinys } Nors, aišku, galima bandyti karpyti :) Trim() metodas. Tiesa, atsibos žaisti...